C096 · Calculus & OptimizationISO 128 · 1:1
Circular Park Divided by Avenue — composite figure at 1:1 scale with dimensions, area 41.63 cm²
A = π·R² − 2·[r·√(R²−r²) + R²·arcsin(r/R)]

High school (grades 11–12) · TypeLab 2D

Circular Park Divided by Avenue

Circular Park Divided by Avenue: a composite plane figure made of a circle of radius 4.4 cm, minus a rectangle 9.6 × 2.2 cm. It is a classic high school (grades 11–12) geometry problem (“Calculus & Optimization”). The net area is 41.63 cm² and the total perimeter is 40.23 cm.

Certified measurements (1:1 scale)

Net area
41.63 cm²
Total perimeter
40.23 cm
Bounding box
8.52 × 8.8 cm
Basic shapes
2
Open in TypeLab 2D

Step-by-step decomposition

  1. 1.Basecircle of radius 4.4 cm60.82 cm²
  2. 2.−rectangle 9.6 × 2.2 cm21.12 cm²

Area of each basic shape before the Boolean composition.

How to find the area

Area formula: A = π·R² − 2·[r·√(R²−r²) + R²·arcsin(r/R)]

The parts overlap or intersect, so the net area (41.63 cm²) comes from the exact Boolean operation rather than from a plain sum of the part areas.

Editable in PowerPoint & Office

The .PPTX file contains native DrawingML shapes: outlines, dimensions and labels stay separate objects you can recolor and edit in PowerPoint, Keynote and Google Slides. The .SVG file is pure vector art at 1:1 scale on an A4 sheet, ready for print, LaTeX and textbook layout.

Composite figures →